Total Pageviews

Category 2

Featured Articles

Decoration

All Stories
Showing posts with label Time And Distance Concepts In Aptitude For Competitive Exams Like CAT. Show all posts
Showing posts with label Time And Distance Concepts In Aptitude For Competitive Exams Like CAT. Show all posts

Thursday 17 October 2013

Time Speed And Distance Concepts In Aptitude For Competitive Exams


Time And Distance Concepts In Aptitude For Competitive Exams Like CAT, SSC, IBPS Bank PO, IAS, Gate  And Other Government Exams.

1.Relation Between Time, Distance And Speed:
Speed = Distance/Time
  • Speed Is Measured In Metre/Sec Or Kilometre/Hour.
  • Time Is Measured In Second Or Minute Or Hour.
  • Distance Is Measured In Metre Or Kilometre.
2.Some Speedy Math Methods To Convert Km/hour To Metre/Sec And Vice Verse:
A.To Convert Km/Hour To Metre/Sec: Km/Hour*5/18 = M/Sec.
B.To Convert Metre/Sec To Km/Hour: Metre/Sec*18/5 = Km/Hour.
3.Concept Of Average Speed:
Average Speed = (Total Distance Traversed/ Total Time In Traversing Distance).
4.Some Important Conditions For Solving Problem Immediately.
A. If Some Distance Is Covered By One Person By Speed P km/hour, And Another Same Distance Is Covered By Q km/hour.
Then
Average Speed = 2PQ/(P+Q) = Harmonic Mean Of Both
B.If Three Equal Distance Is Covered By Speed P Km/hour, Q Km/hour And R km/hour,
Then Average Speed = 2PQR/(PQ+QR+RP)Km/hour = Harmonic Mean Of Above Three.
C. If Three Same Distance Is Covered By P Km/hour, Q km/hour And R km/hour And Takes Equal Amount Of Time Then The
Average Speed = (P+Q+R)/3 Km/Hour.
D. If Two Same Distance Is Covered By P Km/Hour, Q Km/hour In same Amount Of Time, Then
Average Speed = (P+Q)/2 Km/hour.
5.Ratio Relation Among Time, Distance And Speed:
If Speed Of  Ram And Ramesh In The Ratio Of P/Q Then Distance Traversed By These Person In The Ratio P/Q And Time Contained In The Ratio Of Q/P.
6.Relative Speed Comcept:
If Two Objects Are Moving In Same Direction With P Km/hour And Q Km/hour Then
Relative speed = (P-Q)Km/hour If P>Q
(Q-P)Km/hour If Q>P
If Two Objects Are Moving In Opposite Direction With Speed P Km/hour And Q km/hour Then
Relative Speed = (P+Q)Km/hour.

Notes: Two Bikes B1 And B2 Starts From Home H1 And H2 And Reached To H2 And H1 By Travelling Towards Each Other And Take Time T1 And T2 Then Their Raito Of Speed = T2^1/2/T1^1/2 = (Underroot Of T2/Underroot Of T1)
7.Train Relative Speed Problems:
A. Moving Train And Stationary Object Problem
There Are Two Conditions For Moving Train And Stationary Object Prblems.
Condition 1: When Object Traversing By Train Is Negligible.
When Train Is Tavelling Towards Pole Or Other Neglegible Length Object And Cross The Particular Object Then
Speed Of The Train = (Length Of The Train)/Time taken To Traversing The Pole)
When We Take Speed = S, Length Of The Train = L, Time Taken To Cross The Pole = T
Then Formula Of Speed Would Become S = (L/T).
Condition 2: When Object Traversing By Train Is Not Negligible.
When Train Is Travelling Towards The Length Object,And
Length Of The Train = L
Length Of The Object = K
Time For Crossing The Object= T
Then, The Speed Of Train For Crossing The Object Is:
Speed = [(Length Of Train + Length Of Object)/Time Take For Crossing The Length Object]
S = (L+K)/T.
B.Moving Train And Moving Object Of Negligible Length:
Condition 1: When Train And Moving Object(Zero Length) Are Moving Towards Each Other With Respective Speeds P And Q Then
Relative speed = (P+Q).
(P+Q) = [Length of The Train/Time Taken For Crossing The Object].
When We Take Length Of Train = L
Time Taken For Crossing The Object: T
(P+Q) = L/T
Condition 2: When Train And Moving Object(Zero Length) Are Moving In Same Direction With Speed P And Q Then
Relative Speed = (P-Q) = [Length Of Train/Time Taken For Crossing Each Other]
Take Length Of Train = L
Time Taken For Crossing The Object: T
Relative Speed = (P-Q) = L/T.
C:Moving Train And Moving Object Of Some Length
Condition1:When Train Of Length L1 And Moving Object Of Length L2 Are Moving Each Other With Speed P And Q Then,
(P+Q) = [(Length Of Train + Length Of Moving Object)/ Time Taken For Crossing Each Other]
(P+Q) = [L1+L2]/T
Condition 2:When Train Of Length L1 And Moving Object Of Length L2 Are Moving In Same Direction With Speed P And Q Then
(p-Q)= [L1-L2]/T




Quantities aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT),MAT, GMAT, IBPS 

Exam, CSAT, CLAT , Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense 

Competitive Exams, L.I.C/ G. I.C Competitive Exams , Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test 

(IT Companies) and etc, Government Exams etc ,Quantitative Aptitude For Competitive Examinations by R. S. Aggarwal , Quantitative Aptitude Book 

Description. Quantitative Aptitude for Competitive Examination (Fully Solved) Bank P.O, S.B.I. P.O; I.B.P.S; R.B.i. Exam
03:59 - By Unknown 0

back to top