Time And Work Concepts In Aptitude For Competitive Exams Like SSC, IBPS Bank PO And Other Government Exams.
Concepts And Tips For Solving Problems In Less Amount Of Time:
1.Every Work Would Be Treated As 1.
2.A Man can Do Piece Of Work In M Days, Then He Will Work In 1 Day= 1/M Work.
3.If A Man Can Do 1/M Work In One Day, Then He Will Complete The Entire Work In M Days.
4.If A Person Complete A Work In M Days And Another Person Complete The Same Work In N Days Then They Both Complete The Work In MN/(M+N) Days.
5.Work Efficiency Of A Person Is Inversely Propotional To Time. If One Person More Efficient From Other Person, It Means He Complete His Work In Less Amount Of Time Than Other Person.
6.Key Formula For Solving Most Of The Problems: M1N1=M2N2
M=Number Of Men Involved In It.
N=Number Of Days Used.
Example1. A Can Do Piece Of Work In 5 Days And Same Work Would Be Done By B In 8 Days. In How Many Days They Both Completed Work Together?
Solution: According To Above Formula: MN/(M+N)
5*8/(5+8) = 40/13 = 3.07 Days
Alternate Method:
A Do Piece Of Work In………….. 5 Days
A Will Work In 1 Day = 1/5 Work
B Do Piece Of Work In…………… 8 Days
B Will Work In 1 Day = 1/8 Work
They Together Work In 1 Day = 1/5 + 1/8 = 13/40
They Complete Work In 40/13 Days.
Example2: Ramesh Can Do A Work In 30 Days. He Worked 20 Days And Suresh replaed Him And He Completed Remaining Work In 5 Days.In How Many Days Suresh Will Finish The Work?
Solution: Ramesh Can Work In One Day: 1/30 Work
According To Question Ram Work 20 Days, So He Completed 20*1/20 Work In 20 Days
Ramesh Completed Work In 20 Days: 2/3 Work
Remaining Work= 1-2/3= 1/3
1/3 Work Would Be Completed By Suresh In 5 Days
1 Work Would Be Completed By Suresh In 15 Days
So Answer Is 15 Days.
Example3: Ramesh Is Twice As Good Workman As Suresh, And Finish The Piece Of Work In 10 Days Less Than Suresh.Calculate The Time In Which They Both Complete The Work?
Solution: As We Know, According To Tips Efficiency Is Inversely Propotional To Time.
(X-10)/X = 1/2
X=20
Thus, Ramesh And Suresh Both Do Work In One Day = 1/20 + 1/10 = 3/20
Ramesh And Suresh Both Can Do Work In 20/3 Days.
Quantities aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT),MAT, GMAT, IBPS
Exam, CSAT, CLAT , Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense
Competitive Exams, L.I.C/ G. I.C Competitive Exams , Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test
(IT Companies) and etc, Government Exams etc ,Quantitative Aptitude For Competitive Examinations by R. S. Aggarwal , Quantitative Aptitude Book
Description. Quantitative Aptitude for Competitive Examination (Fully Solved) Bank P.O, S.B.I. P.O; I.B.P.S; R.B.i. Exam
1.Every Work Would Be Treated As 1.
2.A Man can Do Piece Of Work In M Days, Then He Will Work In 1 Day= 1/M Work.
3.If A Man Can Do 1/M Work In One Day, Then He Will Complete The Entire Work In M Days.
4.If A Person Complete A Work In M Days And Another Person Complete The Same Work In N Days Then They Both Complete The Work In MN/(M+N) Days.
5.Work Efficiency Of A Person Is Inversely Propotional To Time. If One Person More Efficient From Other Person, It Means He Complete His Work In Less Amount Of Time Than Other Person.
6.Key Formula For Solving Most Of The Problems: M1N1=M2N2
M=Number Of Men Involved In It.
N=Number Of Days Used.
Example1. A Can Do Piece Of Work In 5 Days And Same Work Would Be Done By B In 8 Days. In How Many Days They Both Completed Work Together?
Solution: According To Above Formula: MN/(M+N)
5*8/(5+8) = 40/13 = 3.07 Days
Alternate Method:
A Do Piece Of Work In………….. 5 Days
A Will Work In 1 Day = 1/5 Work
B Do Piece Of Work In…………… 8 Days
B Will Work In 1 Day = 1/8 Work
They Together Work In 1 Day = 1/5 + 1/8 = 13/40
They Complete Work In 40/13 Days.
Example2: Ramesh Can Do A Work In 30 Days. He Worked 20 Days And Suresh replaed Him And He Completed Remaining Work In 5 Days.In How Many Days Suresh Will Finish The Work?
Solution: Ramesh Can Work In One Day: 1/30 Work
According To Question Ram Work 20 Days, So He Completed 20*1/20 Work In 20 Days
Ramesh Completed Work In 20 Days: 2/3 Work
Remaining Work= 1-2/3= 1/3
1/3 Work Would Be Completed By Suresh In 5 Days
1 Work Would Be Completed By Suresh In 15 Days
So Answer Is 15 Days.
Example3: Ramesh Is Twice As Good Workman As Suresh, And Finish The Piece Of Work In 10 Days Less Than Suresh.Calculate The Time In Which They Both Complete The Work?
Solution: As We Know, According To Tips Efficiency Is Inversely Propotional To Time.
(X-10)/X = 1/2
X=20
Thus, Ramesh And Suresh Both Do Work In One Day = 1/20 + 1/10 = 3/20
Ramesh And Suresh Both Can Do Work In 20/3 Days.
Quantities aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT),MAT, GMAT, IBPS
Exam, CSAT, CLAT , Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense
Competitive Exams, L.I.C/ G. I.C Competitive Exams , Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test
(IT Companies) and etc, Government Exams etc ,Quantitative Aptitude For Competitive Examinations by R. S. Aggarwal , Quantitative Aptitude Book
Description. Quantitative Aptitude for Competitive Examination (Fully Solved) Bank P.O, S.B.I. P.O; I.B.P.S; R.B.i. Exam
